The height of the students at a particular university is normally distributed with a mean of 63 inches and a standard deviation of 3 inches. There are 5000 students at this university. How many students have a height between 60 to 66 inches?
"z=\\frac{x-\\mu}{\\sigma\/\\sqrt n}"
"z_1=\\frac{60-63}{3}=-1.00"
"z_2=\\frac{66-63}{3}=1.00"
"P(60<x<66)=P(z<1)-P(z<-1)=0.8413-0.1587=0.6826"
number of students who have a height between 60 to 66 inches:
"5000\\cdot 0.6826=3413"
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