A traffic study of 2,500 vehicles that passed by a checkpoint showed that their speeds were normally distributed with a mean of 82.5 kph and a standard deviation of 11.5 kph. How many vehicles had a speed of more than 90 kph?
μ=82.5σ=11.5P(X>90)=1−P(X<90)=1−P(Z<90−82.511.5)=1−P(Z<0.652)=1−0.7428=0.2572N=2500×0.2572=643\mu=82.5 \\ \sigma= 11.5 \\ P(X>90) = 1 -P(X<90) \\ = 1 -P(Z< \frac{90-82.5}{11.5}) \\ = 1 -P(Z< 0.652) \\ = 1 -0.7428 \\ = 0.2572 \\ N = 2500 \times 0.2572 = 643μ=82.5σ=11.5P(X>90)=1−P(X<90)=1−P(Z<11.590−82.5)=1−P(Z<0.652)=1−0.7428=0.2572N=2500×0.2572=643
Answer: 643
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