Answer to Question #264472 in Statistics and Probability for Kamogelo Aphane

Question #264472

2. 60 % of the population of a town read either magazine A or magazine




B, and 10% read both.




2.1 If 50% read magazine A, what is the probability that one person,




selected at random, reads magazine B? [3]




2.2 What type of events are A and B? Give a reason for you answer?




[2]




2.3 Draw a venn diagram to illustrate you answer. [3]

1
Expert's answer
2021-11-14T18:07:05-0500

Given "P(A\\cup B)=0.6, P(A\\cap B)=0.1"

2.1


"P(A\\cup B)=P(A)+P(B)-P(A\\cap B)"

Given P(A)=0.5.

Then


"P(B)=P(A\\cup B)+P(A\\cap B)-P(A)"

"=0.6+0.1-0.5=0.2"

The probability that one person, selected at random, reads magazine B is 0.2.


2.2


"P(A)P(B)=0.5(0.2)=0.1=P(A\\cap B)"

Then the events A and B are independent events.


2.3


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