A certain type of storage battery lasts on average, 3.0 years with a standard deviation of 0.5 year. Assuming the battery life is normally distributed, find the probability that a given battery will last more than 2 years.
μ=3.0σ=0.5P(X>2)=1−P(X<2)=1−P(Z<2−30.5)=1−P(Z<−2)=1−0.0227=0.9773\mu=3.0 \\ \sigma= 0.5 \\ P(X>2) = 1 -P(X<2) \\ = 1 -P(Z< \frac{2-3}{0.5}) \\ = 1 -P(Z< -2) \\ = 1 -0.0227 \\ = 0.9773μ=3.0σ=0.5P(X>2)=1−P(X<2)=1−P(Z<0.52−3)=1−P(Z<−2)=1−0.0227=0.9773
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