A traffic study of 2,500 vehicles that passed by a checkpoint showed that their speeds were normally distributed with a mean of 82.5 kph and a standard deviation of 11.5 kph. How many vehicles had a speed of more than 90 kph? *
Solution:
"\\bar x = 82.5"
"s = 11.5"
"P(X>90)=1-P(X\\le90)=1-P(Z\\le\\frac{90-\\bar x}{s})="
"=1-P(Z<\\frac{90-82.5}{11.5})=1-P(Z<0.65)=1-0.74215=0.25785=25.785\\%"
25.785% of 2500 vehicles = "2500 \\times 0.25785=644.625\\approx645"
Thus, 645 vehicles have a speed of more than 90kph.
Comments
Leave a comment