Use the t distribution to find the reliability factor for a confidence interval based on the following
confidence coefficients=0.99 and sample sizes: 24
The confidence coefficientis 0.99
(i.e) 1-α=0.99 ---> α=0.01
"\\frac{\u03b1}{2}=\\frac{0.01}{2}=0.005"
Sample size, n=24
Degrees of freedom=n-1=23
The t – table value with 23d.f is
"t_ {\u03b1\/2}=2.807" (Fromt tables)
Comments
Leave a comment