A study of 415 kindergarten students showed that they have seen on average
5000 hours of television. If the sample standard deviation of the population is
900, find the 95% confidence level of the mean for all students. If a parent
claimed that his children watched 4000 hours, would the claim be believable?
"95\\%CI=(5000-1.966\\frac{900}{\\sqrt{415}},5000+1.966\\frac{900}{\\sqrt{415}})=(4913.2,5086.8)."
The claim is not believable because 4000 does not lie in the confidence interval.
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