In a poker hand consisting of 5 cards, find the probability of holding (a) 3 kings; (b) 4 red cards and 1 club.
for 52 card deck:
a)
P=452⋅351⋅250⋅4849⋅4748=47270725P=\frac{4}{52}\cdot \frac{3}{51}\cdot \frac{2}{50}\cdot \frac{48}{49}\cdot \frac{47}{48}=\frac{47}{270725}P=524⋅513⋅502⋅4948⋅4847=27072547
b)
P=12⋅2551⋅2450⋅2349⋅1348=29919992P=\frac{1}{2}\cdot \frac{25}{51}\cdot \frac{24}{50}\cdot \frac{23}{49}\cdot \frac{13}{48}=\frac{299}{19992}P=21⋅5125⋅5024⋅4923⋅4813=19992299
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment