Construct the 99% confidence interval for the population mean duration of the longdistance calls from the town.
Assumptions:
mean "\\bar{x}= 12"
sample standard deviation s= 2
Sample size n = 100
alpha = 1%
The critical value for α=0.01 and df= n-1= 99 is "t_c = 2.626"
"CI = \\bar{x} \u00b1 t_c \\times \\frac{s}{\\sqrt{n}} \\\\\n\nCI = 12 \u00b1 2.626 \\times \\frac{2}{\\sqrt{100}} \\\\\n\nCI = (11.475, 12.525)"
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