The standard deviation of the running time of a sample of 200 fuses was found to be 110 hours. Find a 99% confidence interval for the standard deviation of all such fuses.
Degrees of freedom df=n-1=200-1=199.
"99\\%CI=(s\\sqrt{\\frac{n-1}{\\chi^2_{0.005}}},s\\sqrt{\\frac{n-1}{\\chi^2_{0.995}}})="
"=(110\\sqrt{\\frac{200-1}{254.14}},110\\sqrt{\\frac{200-1}{151.37}})=(97.34,126.12)."
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