There are 6 ways to get a total of at most 4 in case of toss a pair of fair dice.
= (1,1), (1,2), (1,3), (2,1), (2,2), (3,1)
Probability=FavourableOutcomesTotalOutcomesProbability=\frac{Favourable Outcomes}{Total Outcomes}Probability=TotalOutcomesFavourableOutcomes
Probability=636=0.1667Probability=\frac{6}{36}=0.1667Probability=366=0.1667
This means there is 16.67% probability of getting a total of at most 4 in case of tossing a pair of fair dice.
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