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Answer to Question #255674 in Statistics and Probability for Samson
Question #255674
The probabilities that Audu, Chioma and Yinka pass UTME are 1/3, 2/5 and 3/8 respectively. Find the probability that the three of them will fail the exam
Expert's answer
The events "Audu will fail the exam", "Chioma will fail the exam", and "Yinka will fail the exam" are independent. Then
"=(1-1\/3)(1-2\/5)(1-3\/8)=1\/4"
The probability that the three of them will fail the exam is 1/4.
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