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Answer to Question #255674 in Statistics and Probability for Samson

Question #255674
The probabilities that Audu, Chioma and Yinka pass UTME are 1/3, 2/5 and 3/8 respectively. Find the probability that the three of them will fail the exam
1
Expert's answer
2021-10-26T12:01:10-0400

The events "Audu will fail the exam", "Chioma will fail the exam", and "Yinka will fail the exam" are independent. Then


"P(3\\ will\\ fail\\ the\\ exam)"

"=(1-1\/3)(1-2\/5)(1-3\/8)=1\/4"

The probability that the three of them will fail the exam is 1/4.


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