Question

The probabilities that Audu, Chioma and Yinka pass UTME are 1/3, 2/5 and 3/8 respectively. Find the probability that the three of them will fail the exam

Answer 1

The events "Audu will fail the exam", "Chioma will fail the exam", and "Yinka will fail the exam" are independent. Then

$$P(3\ will\ fail\ the\ exam)$$

$$=(1-1/3)(1-2/5)(1-3/8)=1/4$$

The probability that the three of them will fail the exam is 1/4.