Question #255674
The probabilities that Audu, Chioma and Yinka pass UTME are 1/3, 2/5 and 3/8 respectively. Find the probability that the three of them will fail the exam
1
Expert's answer
2021-10-26T12:01:10-0400

The events "Audu will fail the exam", "Chioma will fail the exam", and "Yinka will fail the exam" are independent. Then


P(3 will fail the exam)P(3\ will\ fail\ the\ exam)

=(1−1/3)(1−2/5)(1−3/8)=1/4=(1-1/3)(1-2/5)(1-3/8)=1/4

The probability that the three of them will fail the exam is 1/4.


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