Solution:
P(A)=13,P(C)=25,P(Y)=38P(A)=\dfrac13,P(C)=\dfrac25,P(Y)=\dfrac38P(A)=31,P(C)=52,P(Y)=83
⇒P(A′)=23,P(C′)=35,P(Y′)=58\Rightarrow P(A')=\dfrac23,P(C')=\dfrac35,P(Y')=\dfrac58⇒P(A′)=32,P(C′)=53,P(Y′)=85
The probability that the three of them will fail the exam=P(A′∩B′∩C′)=P(A'\cap B' \cap C')=P(A′∩B′∩C′)
=23.35.58=14=\dfrac23.\dfrac35.\dfrac58 \\=\dfrac14=32.53.85=41
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