Answer to Question #255672 in Statistics and Probability for Samson

Question

The probabilities that Audu, Chioma and Yinka pass UTME are 1/3, 2/5 and 3/8 respectively. Find the probability that the three of them will fail the exam

Answer 1

Solution:

$P(A)=\dfrac13,P(C)=\dfrac25,P(Y)=\dfrac38$

$\Rightarrow P(A')=\dfrac23,P(C')=\dfrac35,P(Y')=\dfrac58$

The probability that the three of them will fail the exam$=P(A'\cap B' \cap C')$

$=\dfrac23.\dfrac35.\dfrac58 \\=\dfrac14$