Question #255672

The probabilities that Audu, Chioma and Yinka pass UTME are 1/3, 2/5 and 3/8 respectively. Find the probability that the three of them will fail the exam

Expert's answer

Solution:

P(A)=13,P(C)=25,P(Y)=38P(A)=\dfrac13,P(C)=\dfrac25,P(Y)=\dfrac38

⇒P(A′)=23,P(C′)=35,P(Y′)=58\Rightarrow P(A')=\dfrac23,P(C')=\dfrac35,P(Y')=\dfrac58

The probability that the three of them will fail the exam=P(A′∩B′∩C′)=P(A'\cap B' \cap C')

=23.35.58=14=\dfrac23.\dfrac35.\dfrac58 \\=\dfrac14


LATEST TUTORIALS
APPROVED BY CLIENTS