Question #255399

Q.1.2 The time taken to complete a web-based questionnaire is normally distributed, with an average time (μ) of 9 minutes and a standard deviation (σ) of 1.55 minutes. What is the probability that a randomly selected person will take: Q.1.2.1 Between 8 and 8.5 minutes to complete the questionnaire? Interpret your answer. (5) Q.1.2.2 Between 8.75 and 9.75 minutes to complete the questionnaire? Interpret your answer.


Expert's answer

μ=9σ=1.55\mu=9 \\ \sigma = 1.55

1.

P(8<X<8.5)=P(X<8.5)−P(X<8)=P(Z<8.5−91.55)−P(Z<8−91.55)=P(Z<−0.322)−P(Z<−0.645)=0.3737−0.2594=0.1143P(8<X<8.5) = P(X<8.5) -P(X<8) \\ = P(Z< \frac{8.5-9}{1.55}) -P(Z< \frac{8-9}{1.55}) \\ = P(Z< -0.322) -P(Z< -0.645) \\ = 0.3737 -0.2594 \\ = 0.1143

The probability that a randomly selected person will take between 8 and 8.5 minutes to complete the questionnaire is 0.1143.

2.

P(8.75<X<9.75)=P(X<9.75)−P(Z<8.75)=P(Z<9.75−91.55)−P(Z<8.75−91.55)=P(Z<0.4838)−P(Z<−0.161)=0.6858−0.4360=0.2498P(8.75<X<9.75) = P(X<9.75) -P(Z< 8.75) \\ = P(Z< \frac{9.75 -9}{1.55}) -P(Z< \frac{8.75 -9}{1.55} ) \\ =P(Z < 0.4838) -P(Z< -0.161) \\ = 0.6858 -0.4360 \\ = 0.2498

The probability that a randomly selected person will take between 8.75 and 9.75 minutes to complete the questionnaire is 0.2498.


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