Two groups of 100 people each were taken for testing the use of vaccine. 15 persons contracted the disease out of the inoculated persons, while 25 contracted the disease in the other group. Test the efficiency of the vaccine. use X square value (at 5 percent level for one degree of freedom the value of X square - 3.82)
The hypothesis being tested is:
H 0 : The vaccine is not effective
H a : The vaccine is effective
The p-value for X2= 3.82 and df = 1 is 0.0506.
(Using the Excel formula =CHISQ.DIST.RT(3.82,1) the P-value is approximately 0.0506)
Since the p-value (0.0506) is greater than the significance level (0.05), we cannot reject the null hypothesis.
Therefore, we cannot conclude that the vaccine is effective.
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