If a random sample of 50 cups of soda dispensed from a machine showed the mean amount of soda dispensed was 7.9 ounces with s=0.35 ounces, find the confidence level if the margin of error is 0.11904?
n=50xˉ=7.9s=0.35ME=0.11904CI=xˉ±MECI=7.9±0.11904CI=(7.78096,8.01904)n=50 \\ \bar{x} = 7.9 \\ s=0.35 \\ ME = 0.11904 \\ CI = \bar{x} ± ME \\ CI = 7.9 ± 0.11904 \\ CI = (7.78096, 8.01904)n=50xˉ=7.9s=0.35ME=0.11904CI=xˉ±MECI=7.9±0.11904CI=(7.78096,8.01904)
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