Answer to Question #254023 in Statistics and Probability for joyce

Question

A company plans to interview 10 recent graduates for possible employment. The company has four positions open. How many groups of four can the company select?

Answer 1

$N = \frac{10!}{4!(10-4)!} = \frac{7\times 8 \times 9 \times 10}{2 \times 3 \times 4} = 210$