Answer to Question #253817 in Statistics and Probability for Sean Worsham

Question

In a genetics class, 6

 students have GREEN eyes, 3

 students have BLUE eyes, and 11

 have HAZEL eyes. If a single student is picked at random, what is the probability that their eyes are GREEN or HAZEL?

Answer 1

6 students have green eyes = $\frac{6}{20}*100 = 30$

11 students have hazel eyes $=\frac{11}{20}*100 = 55$

20 = number of students

So $\frac{6}{20} + \frac{11}{20} = \frac{17}{20}*100 = 85\%$