P(-2.81>z>1.05)=
"P(-2.81<z<1.05)=P(z<1.05)-P(z<-2.81)"
From Standard Normal Distribution Table,
P(z < 1.05) = 0.85314
P(z < -2.81) = 0.00248
"\\implies P(z<1.05)-P(z<-2.81)= 0.85314-0.00248 = 0.85066"
Hence, "\\boxed{P(-2.81>z>1.05)=0.85066}"
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