Question #252768

Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 12% of all visitors to the website are looking for other websites. Assuming that this estimate is correct, find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.


Expert's answer

Let X denote the number of visitors that are actually looking for the website.

X ~ Bin (n=4, p=0.88)

P(X=x)=(4x)(0.88)x(1−0.88)4−xP(X=2)=(42)(0.88)2(1−0.88)4−2=0.0669P(X=x) = \binom{4}{x}(0.88)^x(1-0.88)^{4-x} \\ P(X=2) = \binom{4}{2}(0.88)^2 (1-0.88)^{4-2} = 0.0669


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