Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 12% of all visitors to the website are looking for other websites. Assuming that this estimate is correct, find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.
Let X denote the number of visitors that are actually looking for the website.
X ~ Bin (n=4, p=0.88)
"P(X=x) = \\binom{4}{x}(0.88)^x(1-0.88)^{4-x} \\\\\n\nP(X=2) = \\binom{4}{2}(0.88)^2 (1-0.88)^{4-2} = 0.0669"
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