A sample of π=18 observations is drawn from a normal population with π=960 and π=220. Find each of the following:
A. π(π >1037)
Probability =
B. π(π <877)
C. π(π>934)
A.
z=xβΞΌΟ/n=1037β960220/18=0.08z=\frac{x-\mu}{\sigma/\sqrt{n}}=\frac{1037-960}{220/\sqrt{18}}=0.08z=Ο/nβxβΞΌβ=220/18β1037β960β=0.08
P(X>1037)=1βP(z<0.08)=1β0.53188=0.46812P(X>1037)=1-P(z<0.08)=1-0.53188=0.46812P(X>1037)=1βP(z<0.08)=1β0.53188=0.46812
B.
z=877β960220/18=β0.09z=\frac{877-960}{220/\sqrt{18}}=-0.09z=220/18β877β960β=β0.09
P(X<877)=P(z<β0.09)=0.46414P(X<877)=P(z<-0.09)=0.46414P(X<877)=P(z<β0.09)=0.46414
C.
z=934β960220/18=β0.03z=\frac{934-960}{220/\sqrt{18}}=-0.03z=220/18β934β960β=β0.03
P(X>934)=1βP(z<β0.03)=1β0.48803=0.51197P(X>934)=1-P(z<-0.03)=1-0.48803=0.51197P(X>934)=1βP(z<β0.03)=1β0.48803=0.51197
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment