Question #248894

The duration of the AstraZeneca Covid-19 vaccine side effect is normally distributed with a mean of 1.5 days and a standard deviation of 0.4 days.


(i) If a AstraZeneca Covid-19 vaccine recipient is selected at random, find the percentage

that the duration of side effect is less than 24 hours. (3 marks)


(ii) 96% of the AstraZeneca Covid-19 vaccine recipients have experienced more than k days of discomfort symptoms. Find the value of k. (3 marks)


(iii) 7 AstraZeneca Covid-19 vaccine recipients are selected randomly, find the probability

that 3 recipients have less than 24 hours of side effect.


Expert's answer

i)

z=x−μσ=1−1.50.4=−1.25z=\frac{x-\mu}{\sigma}=\frac{1-1.5}{0.4}=-1.25


P(x<1)=P(z<−1.25)=0.10565P(x<1)=P(z<-1.25)=0.10565


ii)

P(x>k)=0.96P(x>k)=0.96

P(x<k)=1−0.96=0.04P(x<k)=1-0.96=0.04

z for 0.04:


z=k−μσ=k−1.50.4=−1.25z=\frac{k-\mu}{\sigma}=\frac{k-1.5}{0.4}=-1.25

k=1.5−1.25⋅0.4=1k=1.5-1.25\cdot 0.4=1 day


iii)

Binomial distribution

p=P(x<1)=0.10565p=P(x<1)=0.10565 (from part i))

n=7n=7

P(k=3)=C73p3q4=7!3!4!⋅0.105653⋅(1−0.10565)4=0.0264P(k=3)=C^3_7p^3q^4=\frac{7!}{3!4!}\cdot0.10565^3\cdot(1-0.10565)^4=0.0264


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