A sample of n=18 observations is drawn from a normal population with mean=960 and standard deviation= 220. Find each of the following:
A. P(X>1037)
B. P(C<877)
C. P(X>934)
n = 18
µ = 960
σ = 220
z = (x – µ)/ (σ/"\\sqrt{n}" )
(a) z = (1037 – 960)/(220/"\\sqrt{18}" ) = 1.48
Using technology, P(z > 1.48) = 0.0688
(b) z = (877 – 960)/(220/"\\sqrt{18}" ) = –1.6
Using technology, P(z < –1.6) = 0.0547
(c) z = (934 – 960)/(220/"\\sqrt{18}" ) = –0.5
Using technology, P(z > –0.5) = 0.692
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