Question

All products on an assembly line must pass two inspections. It has been determined that

the probability that the first inspector will miss a defective item is 0.09.

Answer 1

The second inspector inspects only items passed by the first inspector. The probability that a defective item will pass both inspection is as follows:

Pr(defective pass both)=Pr(Pass first ∩ pass $2^{nd}$ )

=Pr(pass first)xPr(pass second passed $1^{st}$ )

=(0.09)(0.01)=0.0009

Hence we can conchude that the defective item win not be regected by either inspector is 0.0009