Question #248070

The head supervisor of three discount pharmacy stores wants to know how many discount coupons are redeemed in his stores. The findings of the survey are listed in the table below. At α=0.01

α=0.01, test the hypothesis that redemption level and location are related. 


                             

1
Expert's answer
2021-10-08T11:21:48-0400

The hypothesis tested here is,

H0:H_0: Redemption level and location are statistically independent

Against

H1H_1 :Redemption level and location are statistically dependent.

To conduct this test, the chi-square test of independence is used as described below.

Let;

EijE_{ij} be the expected cell count for the observed cell count in row ii and column jj.

rir_i be the total count for row ii

cjc_j be the total count for column jj and

nn be the total count given by,

i=13ri=j=13cj=n\displaystyle\sum_{i=1}^3r_i=\displaystyle\sum_{j=1}^3c_j=n

For the data above,

r1=218r_1=218

r2=270r_2=270

r3=112r_3=112 and

c1=c2=c3=200c_1=c_2=c_3=200

n=i=13ri=j=13cj=600n=\displaystyle\sum_{i=1}^3r_i=\displaystyle\sum_{j=1}^3c_j=600

First, the expected cell counts are computed using the formula below,

Eij=(ricj)/nE_{ij}=(r_i*c_j)/n

Therefore,

E11=E12=E13=(218200)/600=72.67(2 decimal places)E_{11}=E_{12}=E_{13}=(218*200)/600=72.67(2\space decimal\space places)

E21=E22=E23=(270200)/600=90E_{21}=E_{22}=E_{23}=(270*200)/600=90

E31=E32=E33=(112200)/600=37.33(2 decimal places)E_{31}=E_{32}=E_{33}=(112*200)/600=37.33(2\space decimal\space places)

The chi-square test statistic is given as,

χc2=i=13j=13(OijEij)2/Eij\chi_c^2=\displaystyle\sum_{i=1}^3\displaystyle\sum_{j=1}^3(O_{ij}-E_{ij})^2/E_{ij}

χc2=(6972.67)2/72.67+(9772.67)2/72.67+(5272.67)2/72.67+(10190)2/90+(9390)2/90+(7690)2/90+(3037.33)2/37.33+(1037.33)2/37.33+(7237.33)2/37.33=71.476(3 decimal places)\chi_{c}^2=(69-72.67)^2/72.67+(97-72.67)^2/72.67+(52-72.67)^2/72.67+(101-90)^2/90+ (93-90)^2/90+(76-90)^2/90+(30-37.33)^2/37.33+(10-37.33)^2/37.33+(72-37.33)^2/37.33=71.476(3\space decimal\space places)

This statistic is compared with the chi-square table value with (r1)(c1)=(31)(31)=22=4(r-1)(c-1)=(3-1)(3-1)=2*2=4 degrees of freedom at α=0.01\alpha=0.01 significance level where rr is the total number of rows and cc is the total number of columns.

It is given as,

χ0.01,42=13.2767\chi_{0.01,4}^2=13.2767

Since the test statistic(χc2=71.476)(\chi_{c}^2=71.476) is greater than the table value(χc2=13.2767)(\chi_{c}^2=13.2767), we reject the null hypothesis and conclude that sufficient evidence exist to show that the redemption level and location are related.


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