Suppose we have a group of 50 TV’s and decide to sample 15. What is the probability that the 15 selected contain the best 5 TV’s?
It follows that the probability "p" that the 15 selected contain the best 5 TV’s is equal to
"p=\\frac{{50 \\choose 5}}{{50 \\choose 15}}=\\frac{\\frac{50!}{5!45!}}{\\frac{50!}{15!35!}}=\\frac{15!35!}{5!45!}\n=\\frac{15\\cdot 14\\cdot 13\\cdot 12\\cdot 11\\cdot 10\\cdot 9\\cdot 8\\cdot 7\\cdot 6}{45\\cdot 44\\cdot 43\\cdot 42\\cdot 41\\cdot 40\\cdot 39\\cdot 38\\cdot 37\\cdot 36}"
"=\\frac{ 7}{ 43\\cdot 41\\cdot 38\\cdot 37\\cdot 3}=\\frac{7}{7436334}."
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