Suppose we have a group of 50 TV’s and decide to sample 15. What is the probability that the 15 selected contain the best 5 TV’s?
It follows that the probability ppp that the 15 selected contain the best 5 TV’s is equal to
p=(505)(5015)=50!5!45!50!15!35!=15!35!5!45!=15⋅14⋅13⋅12⋅11⋅10⋅9⋅8⋅7⋅645⋅44⋅43⋅42⋅41⋅40⋅39⋅38⋅37⋅36p=\frac{{50 \choose 5}}{{50 \choose 15}}=\frac{\frac{50!}{5!45!}}{\frac{50!}{15!35!}}=\frac{15!35!}{5!45!} =\frac{15\cdot 14\cdot 13\cdot 12\cdot 11\cdot 10\cdot 9\cdot 8\cdot 7\cdot 6}{45\cdot 44\cdot 43\cdot 42\cdot 41\cdot 40\cdot 39\cdot 38\cdot 37\cdot 36}p=(1550)(550)=15!35!50!5!45!50!=5!45!15!35!=45⋅44⋅43⋅42⋅41⋅40⋅39⋅38⋅37⋅3615⋅14⋅13⋅12⋅11⋅10⋅9⋅8⋅7⋅6
=743⋅41⋅38⋅37⋅3=77436334.=\frac{ 7}{ 43\cdot 41\cdot 38\cdot 37\cdot 3}=\frac{7}{7436334}.=43⋅41⋅38⋅37⋅37=74363347.
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