We have the next distribution: N(1.70, 0.15). It can be simplified as 1.70 + 0.15*Z, where Z - standart normal distribution.
1) P(1.7+0.15∗Z>1.8)=P(Z>0.67)=0.2514
So, there are 580∗0.2514=146 students(approximately)
2) P(1.7+0.15∗Z<1.5)=P(Z<−1.33)=0.0918
So, there are 580∗0.0918=53students(approximately)
3) P(1.65<1.7+0.15∗Z<1.85)=P(Z<1)−P(Z<−0.33)=0.8413−0.3707=0.4706
So, there are 580∗0.4706=273 students(approximately)
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