We have the next distribution: N(1.70, 0.15). It can be simplified as 1.70 + 0.15*Z, where Z - standart normal distribution.
1) "P(1.7+0.15*Z > 1.8) = P(Z>0.67) = 0.2514"
So, there are "580*0.2514=146" students(approximately)
2) "P(1.7+0.15*Z < 1.5) = P(Z<-1.33) = 0.0918"
So, there are "580*0.0918=53"students(approximately)
3) "P(1.65< 1.7 +0.15*Z<1.85)=P(Z<1) - P(Z<-0.33)= 0.8413 - 0.3707= 0.4706"
So, there are "580*0.4706=273" students(approximately)
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