Suppose that a random variable X has a DISCRETE distribution with probability mass function given as: P(x) = ( x / 2485 if x = 1, 2, . . . , 70 0 Otherwise a) Find P(x > 5) b) Find P(2 ≤ x ≤ 68) c) Find P(x = 70.5)
Solution.
"\u0420(x)=\\begin{Bmatrix}\n \\frac{x}{2485}, \\text{if }x=1,2,...,70 \\\\\n 0, otherwise\n\\end{Bmatrix}"
a)
"P(x>5)=1-P(x\\leq 5)=1-\\frac{1}{2485}-\\frac{2}{2485}-\\frac{3}{2485}-\\frac{4}{2485}-\\frac{5}{2485}=1-\\frac{15}{2485}=\\frac{2470}{2485}=0.994"
b)
"P(2\\leq x\\leq 68)=P(68)-P(2)=\\frac{68}{2485}-\\frac{2}{2485}=\\frac{66}{2485}=0.027"
c)
70.5>70, so 70.5 in otherwise.
"P(x=70.5)=0"
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