Question

Calculate the probabilities of P(z>z0) = 0.7389

Answer 1

$P(Z>Z_0)=0.7389\\ \implies 1-P(Z≤Z_0)=0.7389\\ \implies P(Z≤Z_0)=1-0.7389=0.2611\\ \implies Φ(Z_0)=0.2611\\ \implies Z_0=Φ^{-1}(0.2611)=-0.639958$

Answer $Z_0= - 0.64$