Question #243743
Calculate the probabilities of P(-z0<z<0)= 0.3708
1
Expert's answer
2021-09-30T23:47:29-0400

P(−z0<Z<0)=0.5−P(Z<−z0)P(-z_0<Z<0)=0.5-P(Z<-z_0)

0.5−P(Z<−z0)=0.37080.5-P(Z<-z_0)=0.3708

P(Z<−z0)=0.5−0.3708=0.1292P(Z<-z_0)=0.5-0.3708=0.1292

−z0=−1.13-z_0=-1.13

z0=1.13z_0=1.13


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