Answer to Question #243743 in Statistics and Probability for Jovy

Question

Calculate the probabilities of P(-z0<z<0)= 0.3708

Answer 1

$P(-z_0<Z<0)=0.5-P(Z<-z_0)$

$0.5-P(Z<-z_0)=0.3708$

$P(Z<-z_0)=0.5-0.3708=0.1292$

$-z_0=-1.13$

$z_0=1.13$