Question #243737
Calculate the probabilities of P(1.13<z<1.39)
1
Expert's answer
2021-09-29T11:41:50-0400
P(1.13<z<1.39)=P(z<1.39)−P(z≤1.13)P(1.13<z<1.39)=P(z<1.39)-P(z\leq1.13)

=0.91773556−0.87076189≈0.046974=0.91773556-0.87076189\approx0.046974

P(1.13<z<1.39)=0.046974P(1.13<z<1.39)=0.046974


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