Answer to Question #243737 in Statistics and Probability for Jovy

Question

Calculate the probabilities of P(1.13<z<1.39)

Answer 1

$$P(1.13<z<1.39)=P(z<1.39)-P(z\leq1.13)$$

$$=0.91773556-0.87076189\approx0.046974$$

$$P(1.13<z<1.39)=0.046974$$