Answer to Question #243736 in Statistics and Probability for Jovy

Question

Calculate the probabilities of P(-3.10<z<1.90)

Answer 1

$P(-3.10<z<1.90)= P(0<z<1.9)+P(-3.1<z<0)$

Required probabilities can be found in table of z distribution

$P(-3.1<z<0) = 0.49903$

$P(0<z<1.9) = 0.47128$

$P(-3.10<z<1.90) = 0.49903+0.47128=0.97031$