Answer to Question #243488 in Statistics and Probability for hardik

Question #243488

If X is a R.V with PDF f(x) = x/6 when x = 1, 2, 3 and f(x) = 0, otherwise. Find E(X+2)2

1
Expert's answer
2021-09-29T00:29:41-0400
(x+2)291625p1/62/63/6\begin{matrix} (x+2)^2 & 9 & 16 & 25 \\ p & 1/6 & 2/6 & 3/6 \end{matrix}

E[(X+2)2]=9(16)+16(26)+25(36)=583E[(X+2)^2]=9(\dfrac{1}{6})+16(\dfrac{2}{6})+25(\dfrac{3}{6})=\dfrac{58}{3}

E[(X+2)2]=583E[(X+2)^2]=\dfrac{58}{3}


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