Answer to Question #243380 in Statistics and Probability for saraaaaaaaaaaaaaaa

Question

For a data set of the pulse rates for a sample of adult​ females, the lowest pulse rate is 36 beats per​ minute, the mean of the listed pulse rates is x=71.0 beats per​ minute, and their standard deviation is s=12.3 beats per minute.

Answer 1

Solution:

$\mu=71,\sigma=12.3$

$X\sim N(\mu,\sigma)$

As data is missing, we assume that we need to find $P(X>36)$.

$P(X>36)=1-P(X\le 36) \\=1-P(z\le \dfrac{36-71}{12.3}) \\=1-P(z\le-2.85) \\=P(z<2.85) \\=0.99781$