The body temperature of a group of healthy adults have a bell shaped distribution with a mean of 98.37 and a standard deviation of 0.53. Using the empirical rule, find each approximate percentage.
a) P(97.84<X<98.90)=P(μ−σ<X<μ+σ)=68%.P(97.84<X<98.90)=P(\mu-\sigma<X<\mu+\sigma)=68\%.P(97.84<X<98.90)=P(μ−σ<X<μ+σ)=68%.
b) P(96.78<X<99.96)=P(μ−3σ<X<μ+3σ)=99.7%.P(96.78<X<99.96)=P(\mu-3\sigma<X<\mu+3\sigma)=99.7\%.P(96.78<X<99.96)=P(μ−3σ<X<μ+3σ)=99.7%.
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