Question #24148

The International Air Transport Association survey's business travelers to develop quality rating for transatlantic gateways airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each travelers is ask to provide a rating for the Miami International Airport . The rating obtained from the sample of 50 business travelers follow :


6 4 6 8 7 7 6 3 3 8 10 4 8
7 8 7 5 9 5 8 4 3 8 5 5 4
4 4 8 4 5 6 2 5 9 9 8 4 8
9 9 5 9 7 8 3 10 8 9 6

Develop a 95% confidence interval estimate of the population mean rating for Miami.
1

Expert's answer

2013-02-12T10:05:26-0500


Mean value:


X=i=1NxiN=6.34X = \frac {\sum_ {i = 1} ^ {N} x _ {i}}{N} = 6. 3 4


Standard deviation:


σ(r)=1N1i=1N(xir)2.\sigma (r) = \sqrt {\frac {1}{N - 1} \sum_ {i = 1} ^ {N} (x _ {i} - r) ^ {2}}.

r=X\mathbf{r} = \mathbf{X} - mean value.

σ=2.16\sigma = 2.16

95% confidence interval estimate is 1.96σ=2.161.96=4.231.96\sigma = 2.16^{*}1.96 = 4.23

Answer: 4.23

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