Determine the value c so that each of the following functions can serve as a probability distribution of the discrete random variable X: (b) f(x) = c (2 ) (3 )
( assume 2 & x in same parentheses and 3&3-x) ( x ) (3 - x) , for x = 0, 1, 2
Given the function "f(x)=c*(x)*(3-x)" and "x=0,1,2" ,values for the function of these values are determined by substituting the "x's" in the function "f(x)" as shown below,
"f(0)=c*(0)*(3-0)=0, \nf(1)=c*(1)*(3-1)=2c,\nf(2)=c*(2)(3-2)=2c."
For it to be a probability distribution, it must satisfy the condition, "summation(f(x))=1, \\forall x"
so,
0+2c+2c=1
4c=1
c=1/4
Therefore, a constant c=1/4, makes this function a probability distribution.
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