3.1 The average dividend yield of a random sample of 25 JSE-listed companies this year was found
to be 14.5%, with a sample standard deviation of 3.4%. Assume that dividend yields are
normally distributed.
3.1.1 Calculate, with 90% confidence, the actual mean dividend yield of all JSE-listed
companies this year. Interpret the finding. (6)
3.1.2 Calculate, with 95% confidence, the actual mean dividend yield of all JSE-listed
companies this year. Compare the interval with the one calculated in 3.1.1.
(12
1
Expert's answer
2021-09-17T03:44:15-0400
3.1.1
The critical value for α=0.1 is zc=z1−α/2=1.6449.
The corresponding confidence interval is computed as shown below:
CI=(xˉ−zc×nσ,xˉ−zc×nσ)
=(0.145−1.6449×250.034,0.145+1.6449×250.034)
=(0.1338,0.1562)
Therefore, based on the data provided, the 90 % confidence interval for the population mean is 0.1338<μ<0.1562, which indicates that we are 90% confident that the true population mean μ is contained by the interval (0.1338,0.1562),
(13.38%,15.62%)
3.1.2
The critical value for α=0.05 is zc=z1−α/2=1.96.
The corresponding confidence interval is computed as shown below:
CI=(xˉ−zc×nσ,xˉ−zc×nσ)
=(0.145−1.95×250.034,0.145+1.96×250.034)
=(0.1317,0.1583)
Therefore, based on the data provided, the 95 % confidence interval for the population mean is 0.1317<μ<0.1583, which indicates that we are 95% confident that the true population mean μ is contained by the interval (0.1317,0.1583),
(13.17%,15.83%)
We find that the 95% confidence level has a wider interval as compared to the 90% confidence interval.
Increasing the confidence level increases the error bound, making the confidence interval wider. Decreasing the confidence level decreases the error bound, making the confidence interval narrower.
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