Question #238261
3.1 The average dividend yield of a random sample of 25 JSE-listed companies this year was found
to be 14.5%, with a sample standard deviation of 3.4%. Assume that dividend yields are
normally distributed.
3.1.1 Calculate, with 90% confidence, the actual mean dividend yield of all JSE-listed
companies this year. Interpret the finding. (6)
3.1.2 Calculate, with 95% confidence, the actual mean dividend yield of all JSE-listed
companies this year. Compare the interval with the one calculated in 3.1.1.
(12
1
Expert's answer
2021-09-17T03:44:15-0400

3.1.1

The critical value for α=0.1\alpha=0.1 is zc=z1α/2=1.6449.z_c=z_{1-\alpha/2}=1.6449.

The corresponding confidence interval is computed as shown below:


CI=(xˉzc×σn,xˉzc×σn)CI=(\bar{x}-z_c\times\dfrac{\sigma}{\sqrt{n}}, \bar{x}-z_c\times\dfrac{\sigma}{\sqrt{n}})

=(0.1451.6449×0.03425,0.145+1.6449×0.03425)=(0.145-1.6449\times\dfrac{0.034}{\sqrt{25}}, 0.145+1.6449\times\dfrac{0.034}{\sqrt{25}})

=(0.1338,0.1562)=(0.1338, 0.1562)

Therefore, based on the data provided, the 90 % confidence interval for the population mean is 0.1338<μ<0.1562,0.1338<\mu<0.1562, which indicates that we are 90% confident that the true population mean μ\mu is contained by the interval (0.1338,0.1562),(0.1338, 0.1562),

(13.38%,15.62%)(13.38\%, 15.62\%)


3.1.2

The critical value for α=0.05\alpha=0.05 is zc=z1α/2=1.96.z_c=z_{1-\alpha/2}=1.96.

The corresponding confidence interval is computed as shown below:


CI=(xˉzc×σn,xˉzc×σn)CI=(\bar{x}-z_c\times\dfrac{\sigma}{\sqrt{n}}, \bar{x}-z_c\times\dfrac{\sigma}{\sqrt{n}})

=(0.1451.95×0.03425,0.145+1.96×0.03425)=(0.145-1.95\times\dfrac{0.034}{\sqrt{25}}, 0.145+1.96\times\dfrac{0.034}{\sqrt{25}})

=(0.1317,0.1583)=(0.1317, 0.1583)

Therefore, based on the data provided, the 95 % confidence interval for the population mean is 0.1317<μ<0.1583,0.1317<\mu<0.1583, which indicates that we are 95% confident that the true population mean μ\mu is contained by the interval (0.1317,0.1583),(0.1317, 0.1583),

(13.17%,15.83%)(13.17\%, 15.83\%)


We find that the 95% confidence level has a wider interval as compared to the 90% confidence interval.

Increasing the confidence level increases the error bound, making the confidence interval wider. Decreasing the confidence level decreases the error bound, making the confidence interval narrower.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS