Question #238134
The mean lifetime of a sample of 144 fluorescent light bulbs produced by a company is computed to be 170 hours with standard deviation of 120 hours.Test the company's claim that its bulbs' mean time is 200 hours at 0.05 significance level
1
Expert's answer
2021-09-17T03:49:51-0400

The following null and alternative hypotheses need to be tested:

H0:μ=200H_0:\mu=200

H1:μ200H_1:\mu\not=200

This corresponds to a two-tailed test, for which a t-test for one mean, with unknown population standard deviation, using the sample standard deviation, will be used.

Based on the information provided, the significance level is α=0.05,\alpha=0.05,

df=n1=1441=143df=n-1=144-1=143 degrees of freedom, and the critical value for a two-tailed test is tc=1.976692.t_c=1.976692.

The rejection region for this two-tailed test is R={t:t>1.976692}.R=\{t:|t|>1.976692\}.

The t-statistic is computed as follows:


t=xμs/n=170200120/144=3t=\dfrac{x-\mu}{s/\sqrt{n}}=\dfrac{170-200}{120/\sqrt{144}}=-3

Since it is observed that t=3>tc=1.976692=tc,|t| = 3 > t_c = 1.976692=t_c, it is then concluded that the null hypothesis is rejected.

Using the P-value approach: The p-value for two-tailed α=0.05,df=143,t=3\alpha=0.05, df=143,t=-3 is p=0.003186,p=0.003186, and since p=0.003186<0.05=α,p=0.003186<0.05=\alpha, it is concluded that the null hypothesis is rejected.

Therefore, there is enough evidence to claim that the population mean μ\mu is different than 200, at the α=0.05\alpha=0.05 significance level.


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