Question #237565

A random sample of 200 male shoppers in Pavilion shopping mall were interviewed to identify their reasons for coming to this particular mall. The factor of ‘I prefer Knox brand in the mall’ was the most important reason for 120 of those interviewed. Estimate the likely percentage of all male shoppers who frequent this shopping mall primarily because of the Knox brand in the mall, using 97.5% confidence limits.


1
Expert's answer
2021-10-12T10:16:09-0400

SOLUTION

The best point estimate available, p^=120200=0.6\hat{p} = \frac{120}{200}=0.6

Given the confidence level, CI = 0.975

α=1CI=10.975=0.025\alpha=1-CI=1-0.975=0.025

Zcritical =Zα2=0.025=Z_{\frac{\alpha}{2}}=0.025 from using the table

SE =p^(1p^)n=0.035=\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=0.035

The margin error, E =Zα2(SE)=0.078=Z_{\frac{\alpha}{2}}*(SE)=0.078

Lower limit =(pE)=0.5224=(\overline{p}-E)=0.5224

Upper limit =(p+E)=0.6776=(\overline{p}+E)=0.6776

The lower percentage =97.50.5224=96.9776%=97.5-0.5224=96.9776\%

The upper percentage =97.5+0.6776=98.1776%=97.5+0.6776=98.1776\%

ANSWER: The likely percentage of all male shoppers visiting the shop will range from 96.9776%96.9776\% to 98.1776%98.1776\%


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