Question #236971

If the standard deviation of hole diameter exceeds 0.01 millimeters, there is an unacceptably high probability that the rivet will not fit. Suppose that in a sample of 15, the standard deviation is 0.008 millimeter. Is there strong evidence to indicate that the standard deviation of hole diameter exceeds 0.01 millimeter? Use α = 0.10.


1
Expert's answer
2021-09-17T03:54:19-0400

Given that n=15n=15 and σ=0.008\sigma=0.008

Ho=s=0.01H_o=s =0.01

H1=s>0.01H_1=s >0.01


By using chi-square test:

(n1)(s2)(s2)\frac{\left(n-1\right)\left(s^2\right)}{\left(s^2\right)}

=14(0.008×0.008)0.0001=\frac{14\left(0.008\times 0.008\right)}{0.0001}

=8.96=8.96

The tabulated value of chi-square deg. of freedom at 14 is 6.57.

Here calculated chisquare> tabulated chi-square.

Therefore, we reject the null hypothesis.

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