If the standard deviation of hole diameter exceeds 0.01 millimeters, there is an unacceptably high probability that the rivet will not fit. Suppose that in a sample of 15, the standard deviation is 0.008 millimeter. Is there strong evidence to indicate that the standard deviation of hole diameter exceeds 0.01 millimeter? Use α = 0.10.
Given that "n=15" and "\\sigma=0.008"
"H_o=s =0.01"
"H_1=s >0.01"
By using chi-square test:
"\\frac{\\left(n-1\\right)\\left(s^2\\right)}{\\left(s^2\\right)}"
"=\\frac{14\\left(0.008\\times 0.008\\right)}{0.0001}"
"=8.96"
The tabulated value of chi-square deg. of freedom at 14 is 6.57.
Here calculated chisquare> tabulated chi-square.
Therefore, we reject the null hypothesis.
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