Question #236735
A continuous random variable X that can assume values between x = 1 and x = 3 has a density
function given by f(x)=1/2.
(a) Show that the area under the curve is equal to 1.
(b) Find P(2 <X< 2.5).
(c) Find P(X ≤ 1.6).
1
Expert's answer
2021-09-15T02:57:56-0400

(a) Area under the curve is

=13f(x)dx=1312dx=[x2]13=312=22=1= \int^3_1 f(x)dx = \int^3_1 \frac{1}{2} dx = [\frac{x}{2}]^3_1 \\ = \frac{3-1}{2} = \frac{2}{2} = 1

(b) P(2<X<2.5)=22.512dxP(2<X<2.5) = \int^{2.5}_2 \frac{1}{2} dx

=2.522=0.52=0.25= \frac{2.5-2}{2} = \frac{0.5}{2} = 0.25

(c) P(X1.6)=11.6f(x)dx=11.612dxP(X≤1.6) = \int^{1.6}_1 f(x)dx = \int^{1.6}_1 \frac{1}{2} dx

=12(1.61)=0.62=0.3= \frac{1}{2} (1.6 -1) = \frac{0.6}{2} = 0.3


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