Probability function of the random variable X is
f(x) = k/(2^x) , where x = 0,1,2,...
a. Compute k
b. Compute P(X ≥ 6)
c. Compute P(1 ≤ X ≤ 6)
a) 1=∑x=0∞P(X=x)=∑x=0∞k2x=2k1=\sum\limits_{x=0}^{\infty}P(X=x)=\sum\limits_{x=0}^{\infty}\frac{k}{2^x}=2k1=x=0∑∞P(X=x)=x=0∑∞2xk=2k, hence, k=1/2k=1/2k=1/2.
b) P(X≥6)=∑x=6∞P(X=x)=∑x=6∞12x+1=2−71−12=164P(X \geq 6)=\sum\limits_{x=6}^{\infty}P(X=x)=\sum\limits_{x=6}^{\infty}\frac{1}{2^{x+1}}=\frac{2^{-7}}{1-\frac{1}{2}}=\frac{1}{64}P(X≥6)=x=6∑∞P(X=x)=x=6∑∞2x+11=1−212−7=641
c) P(1≤X≤6)=∑x=16P(X=x)=14+18+116+132+164+1128=63128P(1 ≤ X ≤ 6)=\sum\limits_{x=1}^{6}P(X=x)=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}=\frac{63}{128}P(1≤X≤6)=x=1∑6P(X=x)=41+81+161+321+641+1281=12863
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