Question #236315

Probability function of the random variable X is

f(x) = k/(2^x) , where x = 0,1,2,...


a. Compute k

b. Compute P(X ≥ 6)

c. Compute P(1 ≤ X ≤ 6)


1
Expert's answer
2021-09-13T00:30:20-0400

a) 1=x=0P(X=x)=x=0k2x=2k1=\sum\limits_{x=0}^{\infty}P(X=x)=\sum\limits_{x=0}^{\infty}\frac{k}{2^x}=2k, hence, k=1/2k=1/2.

b) P(X6)=x=6P(X=x)=x=612x+1=27112=164P(X \geq 6)=\sum\limits_{x=6}^{\infty}P(X=x)=\sum\limits_{x=6}^{\infty}\frac{1}{2^{x+1}}=\frac{2^{-7}}{1-\frac{1}{2}}=\frac{1}{64}

c) P(1X6)=x=16P(X=x)=14+18+116+132+164+1128=63128P(1 ≤ X ≤ 6)=\sum\limits_{x=1}^{6}P(X=x)=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}=\frac{63}{128}


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Comments

Jim
13.09.21, 11:47

Thank you so much!!

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