Question

Find the mean of a random variable z? z 0 1 2 3 f(z) 1/6 2/6 2/6 1/6

Answer 1

E(Z) =$\sum z. f(z)$

=$(0*\frac 16+1*\frac 2 6+2*\frac 2 6+3*\frac 1 6)$

=$\frac 96$

=1.5