The result of a survey shows that the amount of time a student spends on studying for a test is normally distributed. If the amount of time spent studying is 12 hours and the standard deviation is 4 hours, what is the probability that a student will spend more than 8 hours studying?
"\\mu=12 \\\\\n\\sigma=4 \\\\\nP(X>8) = 1 -P(X\u22648) \\\\\n= 1 -P(Z\u2264 \\frac{8-12}{4}) \\\\\n= 1 -P(Z\u2264 -1) \\\\\n= 1 -0.1586 \\\\\n= 0.8414"
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