Let P(X=1)=P(X=3)=P(x=5)=a.P(X=1)=P(X=3)=P(x=5)=a.P(X=1)=P(X=3)=P(x=5)=a.
Then P(X=2)=P(X=4)=P(x=6)=3a.P(X=2)=P(X=4)=P(x=6)=3a.P(X=2)=P(X=4)=P(x=6)=3a.
Hence
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