By condition,
a=20 σ=10.5a = 20\,\,\sigma = 10.5a=20σ=10.5
Let's find the probability
P(x>25)=Φ(∞)−Φ(25−aσ)=0.5−Φ(25−2010.5)=0.5−Φ(0.48)≈0.5−0.1844=0.3156P(x > 25) = \Phi \left( \infty \right) - \Phi \left( {\frac{{25 - a}}{\sigma }} \right) = 0.5 - \Phi \left( {\frac{{25 - 20}}{{10.5}}} \right) = 0.5 - \Phi \left( {0.48} \right) \approx 0.5 - 0.1844 = 0.3156P(x>25)=Φ(∞)−Φ(σ25−a)=0.5−Φ(10.525−20)=0.5−Φ(0.48)≈0.5−0.1844=0.3156
Answer: P(x>25)≈0.3156P(x > 25) \approx 0.3156P(x>25)≈0.3156
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments