Solution:
μ=12,σ=4X∼N(μ,σ)\mu=12,\sigma=4 \\X\sim N(\mu,\sigma)μ=12,σ=4X∼N(μ,σ)
P(X≥20)=1−P(X<20)=1−P(z<20−124)=1−P(z<2)=1−0.97725=0.02275P(X\ge20)=1-P(X<20) \\=1-P(z<\dfrac{20-12}{4}) \\=1-P(z<2) \\=1-0.97725 \\=0.02275P(X≥20)=1−P(X<20)=1−P(z<420−12)=1−P(z<2)=1−0.97725=0.02275
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