Question #229018

1.3 A random sample of 200 male shoppers in Pavilion shopping mall were interviewed to identify their reasons for coming to this particular mall. The factor of ‘I prefer Knox brand in the mall’ was the most important reason for 120 of those interviewed. Estimate the likely percentage of all male shoppers who frequent this shopping mall primarily because of the Knox brand in the mall, using 97.5% confidence limits. (10)


1
Expert's answer
2021-09-01T11:58:57-0400

Solution:

Given: sample Size =n=200

no. of success =x=120

Point estimate (pˉ)=xn=0.600(\bar{p})=\dfrac{x}{n}=0.600

Confidence Level (CL)=0.975

α=1CL=0.025\alpha=1-\mathrm{CL}=0.025

Zcritical =Zα/2=2.24 [Using tables] Standard Error(SE )=p^(1p^)n=0.035 margin of error(E) =Zα/2(SE)=0.078 Lower Limit =pˉE=0.5224 Upper Limit =pˉ+E=0.6776Thus, 97.5 % confidence interval estimate is (0.5224,0.6776)\begin{aligned} Z_{\text {critical }}=Z_{\alpha / 2}=& 2.24 \quad \text { [Using tables}] \end{aligned} \\\text { Standard Error(SE })=\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}=0.035 \\ \text { margin of error(E) }=Z_{\alpha / 2}(\mathrm{SE}) =0.078 \\ \text { Lower Limit }=\bar{p}-\mathrm{E}=0.5224 \\ \text { Upper Limit }=\bar{p}+\mathrm{E}=0.6776 \\ \text{Thus, 97.5 \% confidence interval estimate is (0.5224,0.6776)}


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