Answer to Question #228755 in Statistics and Probability for juno

Question

in a school 48% of students are hiv positive and 19% are hiv/tb positive ,what is the probability of a student to be tb positive given that students are hiv positive?

Answer 1

$$P(hiv)=0.48, P(hiv\cap tb)=0.19$$

$$P(tb|hiv)=\dfrac{P(hiv\cap tb)}{P(hiv)}=\dfrac{0.19}{0.48}\approx0.3958$$